Integrand size = 21, antiderivative size = 19 \[ \int \cot ^2(e+f x) \left (a+b \sec ^2(e+f x)\right ) \, dx=-a x-\frac {(a+b) \cot (e+f x)}{f} \]
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Time = 0.06 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {4226, 1816, 209} \[ \int \cot ^2(e+f x) \left (a+b \sec ^2(e+f x)\right ) \, dx=-\frac {(a+b) \cot (e+f x)}{f}-a x \]
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Rule 209
Rule 1816
Rule 4226
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {a+b \left (1+x^2\right )}{x^2 \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{f} \\ & = \frac {\text {Subst}\left (\int \left (\frac {a+b}{x^2}-\frac {a}{1+x^2}\right ) \, dx,x,\tan (e+f x)\right )}{f} \\ & = -\frac {(a+b) \cot (e+f x)}{f}-\frac {a \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\tan (e+f x)\right )}{f} \\ & = -a x-\frac {(a+b) \cot (e+f x)}{f} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.08 (sec) , antiderivative size = 43, normalized size of antiderivative = 2.26 \[ \int \cot ^2(e+f x) \left (a+b \sec ^2(e+f x)\right ) \, dx=-\frac {b \cot (e+f x)}{f}-\frac {a \cot (e+f x) \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},1,\frac {1}{2},-\tan ^2(e+f x)\right )}{f} \]
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Time = 0.57 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.74
method | result | size |
derivativedivides | \(\frac {a \left (-\cot \left (f x +e \right )-f x -e \right )-b \cot \left (f x +e \right )}{f}\) | \(33\) |
default | \(\frac {a \left (-\cot \left (f x +e \right )-f x -e \right )-b \cot \left (f x +e \right )}{f}\) | \(33\) |
risch | \(-a x -\frac {2 i a}{f \left ({\mathrm e}^{2 i \left (f x +e \right )}-1\right )}-\frac {2 i b}{f \left ({\mathrm e}^{2 i \left (f x +e \right )}-1\right )}\) | \(46\) |
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none
Time = 0.25 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.79 \[ \int \cot ^2(e+f x) \left (a+b \sec ^2(e+f x)\right ) \, dx=-\frac {a f x \sin \left (f x + e\right ) + {\left (a + b\right )} \cos \left (f x + e\right )}{f \sin \left (f x + e\right )} \]
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\[ \int \cot ^2(e+f x) \left (a+b \sec ^2(e+f x)\right ) \, dx=\int \left (a + b \sec ^{2}{\left (e + f x \right )}\right ) \cot ^{2}{\left (e + f x \right )}\, dx \]
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none
Time = 0.27 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.32 \[ \int \cot ^2(e+f x) \left (a+b \sec ^2(e+f x)\right ) \, dx=-\frac {{\left (f x + e\right )} a + \frac {a + b}{\tan \left (f x + e\right )}}{f} \]
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Leaf count of result is larger than twice the leaf count of optimal. 53 vs. \(2 (19) = 38\).
Time = 0.30 (sec) , antiderivative size = 53, normalized size of antiderivative = 2.79 \[ \int \cot ^2(e+f x) \left (a+b \sec ^2(e+f x)\right ) \, dx=-\frac {2 \, {\left (f x + e\right )} a - a \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - b \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + \frac {a + b}{\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )}}{2 \, f} \]
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Time = 19.28 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00 \[ \int \cot ^2(e+f x) \left (a+b \sec ^2(e+f x)\right ) \, dx=-a\,x-\frac {\mathrm {cot}\left (e+f\,x\right )\,\left (a+b\right )}{f} \]
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